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date: Thu, 18 Oct 2007 16:43:52 GMT,    group: uk.education.maths        back       
Cylinder problem   
Hi all

Here's a problem i've been trying to solve but cannot get the same answer as 
the answer given

An open cylinderical container made from sheet metal of uniform thickness, 
has a mass of 800g. When completely filled with water, the total mass is 
15.6kg

What would be the total mass of the cylinderical container full of water 
made from the same sheet metal (of same thickness) but with double the the 
diameter and double the height ?

I make it 124.8kg

but the answer 'should' be 121.6kg

Can anyone help?

TIA

sheri

-- 
Life may not be the party we hoped for, but whilst we are here we might as 
well dance
date: Thu, 18 Oct 2007 16:43:52 GMT   author:   ~Bitzchick~

Re: Cylinder problem   
"~Bitzchick~"  wrote:
>  Hi all
>
> Here's a problem i've been trying to solve but cannot get the same answer
> as the answer given
>
> An open cylinderical container made from sheet metal of uniform
> thickness, has a mass of 800g. When completely filled with water, the
> total mass is 15.6kg
>
> What would be the total mass of the cylinderical container full of water
> made from the same sheet metal (of same thickness) but with double the
> the diameter and double the height ?
>
> I make it 124.8kg

That's presumably because you used 15.6kg * 2^3. But that is incorrect
because it treats the sheet metal as if its thickness also doubled.

The answer you mentioned below is correct. I hope you will now be able to
get it yourself.

David

> but the answer 'should' be 121.6kg
>
> Can anyone help?
>
> TIA
>
> sheri
date: 18 Oct 2007 17:52:31 GMT   author:   David W. Cantrell

Re: Cylinder problem   
David W. Cantrell wrote:
> "~Bitzchick~"  wrote:
>>  Hi all
>>
>> Here's a problem i've been trying to solve but cannot get the same
>> answer as the answer given
>>
>> An open cylinderical container made from sheet metal of uniform
>> thickness, has a mass of 800g. When completely filled with water, the
>> total mass is 15.6kg
>>
>> What would be the total mass of the cylinderical container full of
>> water made from the same sheet metal (of same thickness) but with
>> double the the diameter and double the height ?
>>
>> I make it 124.8kg
>
> That's presumably because you used 15.6kg * 2^3. But that is incorrect
> because it treats the sheet metal as if its thickness also doubled.
>
> The answer you mentioned below is correct. I hope you will now be
> able to get it yourself.
>
Thanks for your response but...
I'm afraid not. Here is my arguable logic...

Density of material =  mass/volumeof material

so volume = mass/density. If density remains constant then volume is 
proportional to mass. So if the volume of the larger cylinder is 8 times 
bigger than the volume of the smaller cylinder, (I proved the maths) then 
the mass of the larger cylinder must be 8 times bigger. I can't see how the 
thickness of the material comes into it?




sheri
date: Thu, 18 Oct 2007 20:58:02 GMT   author:   ~Bitzchick~

Re: Cylinder problem   
David W. Cantrell wrote:
> "~Bitzchick~"  wrote:
>>  Hi all
>>
>> Here's a problem i've been trying to solve but cannot get the same
>> answer as the answer given
>>
>> An open cylinderical container made from sheet metal of uniform
>> thickness, has a mass of 800g. When completely filled with water, the
>> total mass is 15.6kg
>>
>> What would be the total mass of the cylinderical container full of
>> water made from the same sheet metal (of same thickness) but with
>> double the the diameter and double the height ?
>>
>> I make it 124.8kg
>
> That's presumably because you used 15.6kg * 2^3. But that is incorrect
> because it treats the sheet metal as if its thickness also doubled.
>
> The answer you mentioned below is correct. I hope you will now be
> able to get it yourself.
>

Oh I think I've got it

taking the sheet metal as having a length and a width and a thickness

the volume of the metal would be length  x width x thickness

but if the thickness stays the same  and you double the width (diameter) and
the length (the height) BUT keep the thickness the same. You are only
multiplying the length x width, ie 2 x 2 =  4
so if density = mass/volume, so if mass is proportional to volume OF METAL,

then  metal mass of large cylinder is 4 x bigger than metal mass of small
cylinder

So 0.8kg x 4 = 3.2 kg
 therefore new total volume  =  118.4 + 3.2 =  121.6kg

Goodness me!

Thanks David :o))

sheri
date: Thu, 18 Oct 2007 21:27:40 GMT   author:   ~Bitzchick~

Re: Cylinder problem   
In article <uNPRi.33503$c_1.29554@text.news.blueyonder.co.uk>, ~Bitzchick~
 writes
snip
>Density of material =  mass/volumeof material
Snip

-no need to calculate density;

The volume, and hence the mass of water will increase by  a factor of 2x2x2

The AREA of metal, and hence the mass will increase by a factor of 2x2
(for metal of the same thickness) 
-- 
Chris Holford
date: Thu, 18 Oct 2007 22:32:48 +0100   author:   Chris Holford

Re: Cylinder problem   
Chris Holford wrote:
> In article <uNPRi.33503$c_1.29554@text.news.blueyonder.co.uk>,
> ~Bitzchick~  writes
> snip
>> Density of material =  mass/volumeof material
> Snip
>
> -no need to calculate density;
>
> The volume, and hence the mass of water will increase by  a factor of
> 2x2x2
>
> The AREA of metal, and hence the mass will increase by a factor of 2x2
> (for metal of the same thickness)

Yes yes yes. I'm so bloody annoyed to have not considered the metal itself, 
I could kick myself! I thought the question meant that the cylinder was an 
idealised hypothetical solid object and for the sake of rhe question, the 
thickness would stay constant to ease the maths!!

I'm so angry with myself with seeing the question as an exercise and not 
real life, as it were.

I shall crawl into a hole and weep now :-((

I wish I was as clever as you lot

sheri
date: Thu, 18 Oct 2007 23:30:23 GMT   author:   ~Bitzchick~

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