G'day,

marking my son's homework.

S=a+(n-1)d

he arrived at the correct answer

S-(n-1)d

however, he went further and arrived at

S+d-dn

do I mark him correct for condensing further
if not, why?

Thank you.
Rod.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

G'day,

marking my son's homework.

S=a+(n-1)d

he arrived at the correct answer

S-(n-1)d

however, he went further and arrived at

S+d-dn

do I mark him correct for condensing further
if not, why?

Thank you.
Rod.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

G'day,

marking my son's homework.

S=a+(n-1)d

he arrived at the correct answer

S-(n-1)d

however, he went further and arrived at

S+d-dn

do I mark him correct for condensing further
if not, why?

Thank you.
Rod.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that is equivalent to the 
original but has the desired variable isolated on the left.

> however, he went further and arrived at
> 
> S+d-dn
> 
> do I mark him correct for condensing further

This represents an expansion, not a condensation. In isolation, I see 
no particular reason for preferring one form over the other. If this 
problem was part of some larger sequence of operations, it might be 
more helpful to use one form than the other.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.207fa1c0216e38b698aaf1@news.individual.net...

Thank you Mr. Brown.

> I guess you mean that the problem was to solve for a. I hope that was
> stated in the problem and just omitted by you in your article.

Yes, see my subsequent post  (Oops)

> Even so, the correct form of answer would be
> a = S-(n-1)d
> and not what you said. When you solve for a variable, you transform
> the original equation into a new equation that is equivalent to the
> original but has the desired variable isolated on the left.

Thank you, that clarifies it for me in marking his work.

> > however, he went further and arrived at
> > S+d-dn
> > do I mark him correct for condensing further
> This represents an expansion, not a condensation. In isolation, I see
> no particular reason for preferring one form over the other. If this
> problem was part of some larger sequence of operations, it might be
> more helpful to use one form than the other.

Understood,
The student has to get a certain amount of his work correct in an "SCT"
(Standard completion Time) before he is allowed to progress
further along in the set work.
Ergo, how I mark him is important.
The Answer book allocated to me has the following

"3. In H21-40, the form of the answers to the literal equations
can vary depending on the order of the letters and combination
of positive and negative signs. The Answer Book includes only the
typical form as a model; however, mark the students' answer
correct if it is an expression equivalent to the model answer."

Hence, in this case I shall award a correct answer,
but I shall have him read your repsonse for future questions.

Thank you for your time spent on our behalf.
Rodney

Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> The Answer book allocated to me has the following
> 
> "3. The Answer Book includes only the
> typical form as a model; however, mark the students' answer
> correct if it is an expression equivalent to the model answer."

If it actually says that, it is wrong. The possessive of student is 
student's, not students'. I sincerely hope the answer book was drawn 
up with more care in the math than was apparently taken in the 
English.

-- 
Stan Brown, Oak Road Systems, Tompkins County, New York, USA
                                  http://OakRoadSystems.com/

"Stan Brown"  wrote in message
news:MPG.20809f5244d3860198aafe@news.individual.net...
> Fri, 6 Apr 2007 17:03:10 +0800 from Rod :
> > The Answer book allocated to me has the following
> >
> > "3. The Answer Book includes only the
> > typical form as a model; however, mark the students' answer
> > correct if it is an expression equivalent to the model answer."
>
> If it actually says that, it is wrong. The possessive of student is
> student's, not students'. I sincerely hope the answer book was drawn
> up with more care in the math than was apparently taken in the
> English.

It does, it does.
However, in our house, we are more forgiving,
and are happy to allocate the error to "typo"     :)
Cheer up my friend.

"Rod"  wrote in message
news:4615c2f6$1_1@news.iprimus.com.au...


Oops,
meant to add obviously
solving the equation for a

Fri, 6 Apr 2007 11:50:44 +0800 from Rod :
> G'day,
> 
> marking my son's homework.
> 
> S=a+(n-1)d
> 
> he arrived at the correct answer
> 
> S-(n-1)d

I guess you mean that the problem was to solve for a. I hope that was 
stated in the problem and just omitted by you in your article.

Even so, the correct form of answer would be
	a = S-(n-1)d
and not what you said. When you solve for a variable, you transform 
the original equation into a new equation that