spoken word
Sat, 4 Nov 2006 13:02:50 +0400
A BIDMAS topic has got me thinking. I can generate some research from your
thoughts, if you would be so kind. (All acknowledged of course)
Can you please tell me how you would say these examples to your class?
Spoken word.
3 + 4 =
7 - 5 =
-2
+6
+3 - (+5)=
(-3) - (-8) =
What year group(s) ...
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FAQ for newsgroup uk.education.maths
Fri, 03 Nov 2006 07:48:00 GMT
This is the FAQ for uk.education.maths, which is posted weekly to the group,
as well as the group charter posted fortnightly. These are also available
by email from:-
email to: infolist@pcserviceselectronics.co.uk
message of: sendme maths
sendme mathsfaq
end
Thi ...
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Math Grapher & Calculator
2 Nov 2006 22:15:00 -0800
Recommend good math grapher and calculator to you. Just visit
http://www.graphnow.com.
Best Regards
Sincerely
John Smith
---------------------------------------------------------------------------------------------
GraphNow Software
Graphing for mathematics study and research work
http://www.graphnow ...
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Root-Solving History. Newton. Halley. Householder. Bernoulli. Continued Fractions
30 Oct 2006 19:01:53 -0800
NEW EXTREMELY SIMPLE ARITHMETICAL ROOT-SOLVING METHODS
http://mipagina.cantv.net/arithmetic/rmdef.htm
A brief summary on extremely simple higher-order root-solving
algorithms established by agency of the simple arithmetical operation:
'Rational Mean' which is a general and unifying principle of
Quantity tha ...
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Application of the Binomial theorem
Sat, 28 Oct 2006 10:47:00 GMT
As you've been so helpful to me before I wonder if you can give me a *hint*
re the *approach* to the following problem.
I don't want to be given a solution nor an answer, but some hints about how
to *go about* solving it.
I know the binomial theorem but find difficulty in applying it to this
problem:
...
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Exponential equations
Fri, 27 Oct 2006 18:31:28 GMT
I've been given the following problem to solve for x
e^2x - e^-2x = 4
which I have solved for x, by taking natural logs, to give x = 0.3466
However when I substitute the found value of x back into the equation it
doesn't work
I just cannot understand how I can solve for x but it *doesn't* solve for
...
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FAQ for newsgroup uk.education.maths
Fri, 27 Oct 2006 07:48:00 BST
This is the FAQ for uk.education.maths, which is posted weekly to the group,
as well as the group charter posted fortnightly. These are also available
by email from:-
email to: infolist@pcserviceselectronics.co.uk
message of: sendme maths
sendme mathsfaq
end
Thi ...
|
CHARTER for newsgroup uk.education.maths
Fri, 27 Oct 2006 07:48:00 BST
>Date: Sun, 11 Aug 1996 19:05:55 +0100
>From: Richard Letts <control@illuin.demon.co.uk>
>Message-Id: <199608111805.TAA12939@illuin.demon.co.uk>
This is the initial charter for the newsgroup uk.education.maths
as issued in the newgroup message.
Richard Letts control@u ...
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FAQ for newsgroup uk.education.maths
Fri, 20 Oct 2006 07:48:00 BST
This is the FAQ for uk.education.maths, which is posted weekly to the group,
as well as the group charter posted fortnightly. These are also available
by email from:-
email to: infolist@pcserviceselectronics.co.uk
message of: sendme maths
sendme mathsfaq
end
Thi ...
|
what would the workings for this?
18 Oct 2006 03:48:55 -0700
A number pattern is shown as
n^3 + 1 = (n + 1)(n^2 - n + 1) , where ^ = raised to the power of
ie
3^3 + 1 = (3 + 1)(3^2 - 3 + 1)
find an expression for 8p^3 + 1
now I would start with
(8p + 1)(8p^2 - 8p + 1)
but the answer is
(2p + 1)(4p^2 - 2p + 1)
so what is the working to get to ( ...
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